How do you find the derivative of ##sin(x^3)##?

Using the notation provided there, if we define ##y(x) = sin(x^3)## and ##u=x^3##, we may rewrite ##y(x)## as ##y(u)=sin(u)##From the chain rule we know that ##dy/dx = (du)/dx (dy)/(du)##. Recall that...

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