How do you find integral of ##((secxtanx)/(secx-1))dx##?...
How do you find integral of ##((secxtanx)/(secx-1))dx##?
Another way of doing this is to consider that ##d(secx) = secxtanx*dx##
That is, the derivative of ##secx## is ##secxtanx##
##=> int(secxtanx)/(secx - 1)dx = int d(secx)/(secx - 1)##
This is the same ...
